Base | Representation |
---|---|
bin | 11110101110010100000… |
… | …111111110010000100001 |
3 | 21110211200002220000012221 |
4 | 132232110013332100201 |
5 | 234042432344412241 |
6 | 4253531351351041 |
7 | 305352221256124 |
oct | 36562407762041 |
9 | 7424602800187 |
10 | 2111314060321 |
11 | 744448821964 |
12 | 2a122a982481 |
13 | 12413307cc5b |
14 | 7428c3b43bb |
15 | 39dc06415d1 |
hex | 1eb941fe421 |
2111314060321 has 8 divisors (see below), whose sum is σ = 2141212708800. Its totient is φ = 2081419907280.
The previous prime is 2111314060313. The next prime is 2111314060357. The reversal of 2111314060321 is 1230604131112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2111314060321 - 23 = 2111314060313 is a prime.
It is a super-2 number, since 2×21113140603212 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2111314060621) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 172231 + ... + 2062108.
It is an arithmetic number, because the mean of its divisors is an integer number (267651588600).
Almost surely, 22111314060321 is an apocalyptic number.
It is an amenable number.
2111314060321 is a deficient number, since it is larger than the sum of its proper divisors (29898648479).
2111314060321 is a wasteful number, since it uses less digits than its factorization.
2111314060321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2247719.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 2111314060321 its reverse (1230604131112), we get a palindrome (3341918191433).
The spelling of 2111314060321 in words is "two trillion, one hundred eleven billion, three hundred fourteen million, sixty thousand, three hundred twenty-one".
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