Base | Representation |
---|---|
bin | 110000000000010111011101… |
… | …000000000000010011010101 |
3 | 1000200112222002100001022101112 |
4 | 300000113131000000103111 |
5 | 210133134114233313240 |
6 | 2025012233315304405 |
7 | 62320512200646620 |
oct | 6000273500002325 |
9 | 1020488070038345 |
10 | 211131415135445 |
11 | 6130036a728612 |
12 | 1b81a8238ab105 |
13 | 90a67b78053bc |
14 | 3a1cb5a596db7 |
15 | 196202c941665 |
hex | c005dd0004d5 |
211131415135445 has 16 divisors (see below), whose sum is σ = 289580835369600. Its totient is φ = 144761237358144.
The previous prime is 211131415135427. The next prime is 211131415135453. The reversal of 211131415135445 is 544531514131112.
It is a cyclic number.
It is not a de Polignac number, because 211131415135445 - 210 = 211131415134421 is a prime.
It is a super-2 number, since 2×2111314151354452 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 303609470 + ... + 304304079.
It is an arithmetic number, because the mean of its divisors is an integer number (18098802210600).
Almost surely, 2211131415135445 is an apocalyptic number.
It is an amenable number.
211131415135445 is a deficient number, since it is larger than the sum of its proper divisors (78449420234155).
211131415135445 is an equidigital number, since it uses as much as digits as its factorization.
211131415135445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 607923484.
The product of its digits is 144000, while the sum is 41.
Adding to 211131415135445 its reverse (544531514131112), we get a palindrome (755662929266557).
The spelling of 211131415135445 in words is "two hundred eleven trillion, one hundred thirty-one billion, four hundred fifteen million, one hundred thirty-five thousand, four hundred forty-five".
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