Base | Representation |
---|---|
bin | 11110101110010100011… |
… | …111000110101010000001 |
3 | 21110211200112022002001212 |
4 | 132232110133012222001 |
5 | 234042440422432113 |
6 | 4253532125335505 |
7 | 305352323642441 |
oct | 36562437065201 |
9 | 7424615262055 |
10 | 2111320124033 |
11 | 74445119369a |
12 | 2a1230a07595 |
13 | 1241343c3c53 |
14 | 7428d112121 |
15 | 39dc0e3d0a8 |
hex | 1eb947c6a81 |
2111320124033 has 16 divisors (see below), whose sum is σ = 2127592396800. Its totient is φ = 2095107412800.
The previous prime is 2111320124009. The next prime is 2111320124041. The reversal of 2111320124033 is 3304210231112.
It is a cyclic number.
It is not a de Polignac number, because 2111320124033 - 232 = 2107025156737 is a prime.
It is a super-2 number, since 2×21113201240332 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2111320424033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 185214068 + ... + 185225466.
It is an arithmetic number, because the mean of its divisors is an integer number (132974524800).
Almost surely, 22111320124033 is an apocalyptic number.
It is an amenable number.
2111320124033 is a deficient number, since it is larger than the sum of its proper divisors (16272272767).
2111320124033 is a wasteful number, since it uses less digits than its factorization.
2111320124033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13888.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 2111320124033 its reverse (3304210231112), we get a palindrome (5415530355145).
The spelling of 2111320124033 in words is "two trillion, one hundred eleven billion, three hundred twenty million, one hundred twenty-four thousand, thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •