Base | Representation |
---|---|
bin | 11110101110010100011… |
… | …111000110101010001001 |
3 | 21110211200112022002002011 |
4 | 132232110133012222021 |
5 | 234042440422432131 |
6 | 4253532125335521 |
7 | 305352323642452 |
oct | 36562437065211 |
9 | 7424615262064 |
10 | 2111320124041 |
11 | 7444511936a7 |
12 | 2a1230a075a1 |
13 | 1241343c3c5b |
14 | 7428d112129 |
15 | 39dc0e3d0b1 |
hex | 1eb947c6a89 |
2111320124041 has 2 divisors, whose sum is σ = 2111320124042. Its totient is φ = 2111320124040.
The previous prime is 2111320124009. The next prime is 2111320124077. The reversal of 2111320124041 is 1404210231112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2009861948416 + 101458175625 = 1417696^2 + 318525^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111320124041 - 25 = 2111320124009 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111320124141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055660062020 + 1055660062021.
It is an arithmetic number, because the mean of its divisors is an integer number (1055660062021).
Almost surely, 22111320124041 is an apocalyptic number.
It is an amenable number.
2111320124041 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111320124041 is an equidigital number, since it uses as much as digits as its factorization.
2111320124041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 2111320124041 its reverse (1404210231112), we get a palindrome (3515530355153).
The spelling of 2111320124041 in words is "two trillion, one hundred eleven billion, three hundred twenty million, one hundred twenty-four thousand, forty-one".
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