211132203400113 has 4 divisors (see below), whose sum is σ = 281509604533488. Its totient is φ = 140754802266740.

The previous prime is 211132203400061. The next prime is 211132203400141. The reversal of 211132203400113 is 311004302231112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211132203400113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (211132203400813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35188700566683 + ... + 35188700566688.

It is an arithmetic number, because the mean of its divisors is an integer number (70377401133372).

Almost surely, 2^{211132203400113} is an apocalyptic number.

It is an amenable number.

211132203400113 is a deficient number, since it is larger than the sum of its proper divisors (70377401133375).

211132203400113 is an equidigital number, since it uses as much as digits as its factorization.

211132203400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70377401133374.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 211132203400113 its reverse (311004302231112), we get a palindrome (522136505631225).

The spelling of 211132203400113 in words is "two hundred eleven trillion, one hundred thirty-two billion, two hundred three million, four hundred thousand, one hundred thirteen".