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2111323431143 = 6901130594013
BaseRepresentation
bin11110101110010100101…
…011101110000011100111
321110211200202112002120102
4132232110223232003213
5234042442244244033
64253532324254315
7305352364025243
oct36562453560347
97424622462512
102111323431143
11744453042343
122a1231b4139b
13124134cb1314
147428d733423
1539dc1392de8
hex1eb94aee0e7

2111323431143 has 4 divisors (see below), whose sum is σ = 2111354094168. Its totient is φ = 2111292768120.

The previous prime is 2111323431127. The next prime is 2111323431149. The reversal of 2111323431143 is 3411343231112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2111323431143 - 24 = 2111323431127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111323431149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15227996 + ... + 15366017.

It is an arithmetic number, because the mean of its divisors is an integer number (527838523542).

Almost surely, 22111323431143 is an apocalyptic number.

2111323431143 is a deficient number, since it is larger than the sum of its proper divisors (30663025).

2111323431143 is an equidigital number, since it uses as much as digits as its factorization.

2111323431143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30663024.

The product of its digits is 5184, while the sum is 29.

Adding to 2111323431143 its reverse (3411343231112), we get a palindrome (5522666662255).

The spelling of 2111323431143 in words is "two trillion, one hundred eleven billion, three hundred twenty-three million, four hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 69011 30594013 2111323431143