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211132405613 = 1921110990183
BaseRepresentation
bin1100010010100001111…
…0001101011101101101
3202011222011212111002102
43010220132031131231
511424344343434423
6240554244104445
721153025560023
oct3045036153555
9664864774072
10211132405613
11815a4814318
1234b03995125
1316ba97c522c
14a30c7ba713
15575a969c28
hex312878d76d

211132405613 has 4 divisors (see below), whose sum is σ = 211143415008. Its totient is φ = 211121396220.

The previous prime is 211132405541. The next prime is 211132405619. The reversal of 211132405613 is 316504231112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211132405613 - 28 = 211132405357 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211132405619) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5475881 + ... + 5514302.

It is an arithmetic number, because the mean of its divisors is an integer number (52785853752).

Almost surely, 2211132405613 is an apocalyptic number.

It is an amenable number.

211132405613 is a deficient number, since it is larger than the sum of its proper divisors (11009395).

211132405613 is a wasteful number, since it uses less digits than its factorization.

211132405613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11009394.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 211132405613 its reverse (316504231112), we get a palindrome (527636636725).

The spelling of 211132405613 in words is "two hundred eleven billion, one hundred thirty-two million, four hundred five thousand, six hundred thirteen".

Divisors: 1 19211 10990183 211132405613