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211135200000 = 2835587973
BaseRepresentation
bin1100010010100010100…
…0110111101100000000
3202011222101010110021020
43010220220313230000
511424401102400000
6240554424025440
721153061405644
oct3045050675400
9664871113236
10211135200000
11815a635282a
1234b04902280
1316baa26310a
14a30cd06c24
15575ad1cba0
hex3128a37b00

211135200000 has 216 divisors, whose sum is σ = 702372451536. Its totient is φ = 56302080000.

The previous prime is 211135199971. The next prime is 211135200011. The reversal of 211135200000 is 2531112.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2356014 + ... + 2443986.

Almost surely, 2211135200000 is an apocalyptic number.

211135200000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211135200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (351186225768).

211135200000 is an abundant number, since it is smaller than the sum of its proper divisors (491237251536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211135200000 is an frugal number, since it uses more digits than its factorization.

211135200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88017 (or 87983 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 211135200000 its reverse (2531112), we get a palindrome (211137731112).

The spelling of 211135200000 in words is "two hundred eleven billion, one hundred thirty-five million, two hundred thousand".