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21113680597 = 118717787431
BaseRepresentation
bin10011101010011110…
…010011001011010101
32000111110010002211021
4103222132103023111
5321220100234342
613411031241141
71345134216052
oct235236231325
960443102737
1021113680597
118a55138809
124112b191b1
131cb6338539
141044186029
15838905567
hex4ea7932d5

21113680597 has 4 divisors (see below), whose sum is σ = 21131469216. Its totient is φ = 21095891980.

The previous prime is 21113680591. The next prime is 21113680613. The reversal of 21113680597 is 79508631112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21113680597 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21113680591) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8892529 + ... + 8894902.

It is an arithmetic number, because the mean of its divisors is an integer number (5282867304).

Almost surely, 221113680597 is an apocalyptic number.

It is an amenable number.

21113680597 is a deficient number, since it is larger than the sum of its proper divisors (17788619).

21113680597 is a wasteful number, since it uses less digits than its factorization.

21113680597 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17788618.

The product of its (nonzero) digits is 90720, while the sum is 43.

The spelling of 21113680597 in words is "twenty-one billion, one hundred thirteen million, six hundred eighty thousand, five hundred ninety-seven".

Divisors: 1 1187 17787431 21113680597