211140113 has 4 divisors (see below), whose sum is σ = 211271988. Its totient is φ = 211008240.

The previous prime is 211140091. The next prime is 211140133. The reversal of 211140113 is 311041112.

211140113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 119421184 + 91718929 = 10928^2 + 9577^2 .

It is a cyclic number.

It is not a de Polignac number, because 211140113 - 2⁶ = 211140049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (211140133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63506 + ... + 66747.

It is an arithmetic number, because the mean of its divisors is an integer number (52817997).

Almost surely, 2^211140113 is an apocalyptic number.

It is an amenable number.

211140113 is a deficient number, since it is larger than the sum of its proper divisors (131875).

211140113 is a wasteful number, since it uses less digits than its factorization.

211140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131874.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 211140113 is about 14530.6611343049. The cubic root of 211140113 is about 595.4659279197.

Adding to 211140113 its reverse (311041112), we get a palindrome (522181225).

Subtracting 211140113 from its reverse (311041112), we obtain a palindrome (99900999).

It can be divided in two parts, 2111 and 40113, that added together give a palindrome (42224).

The spelling of 211140113 in words is "two hundred eleven million, one hundred forty thousand, one hundred thirteen".