21114013120433 has 4 divisors (see below), whose sum is σ = 21116002579188. Its totient is φ = 21112023661680.

The previous prime is 21114013120411. The next prime is 21114013120439. The reversal of 21114013120433 is 33402131041112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 21056140157809 + 57872962624 = 4588697^2 + 240568^2 .

It is a cyclic number.

It is not a de Polignac number, because 21114013120433 - 2¹² = 21114013116337 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (21114013120439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 994713458 + ... + 994734683.

It is an arithmetic number, because the mean of its divisors is an integer number (5279000644797).

Almost surely, 2^{21114013120433} is an apocalyptic number.

It is an amenable number.

21114013120433 is a deficient number, since it is larger than the sum of its proper divisors (1989458755).

21114013120433 is a wasteful number, since it uses less digits than its factorization.

21114013120433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1989458754.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 21114013120433 its reverse (33402131041112), we get a palindrome (54516144161545).

The spelling of 21114013120433 in words is "twenty-one trillion, one hundred fourteen billion, thirteen million, one hundred twenty thousand, four hundred thirty-three".