Base | Representation |
---|---|
bin | 1001100110011111111010… |
… | …10000000111011110110111 |
3 | 2202202110221212200112211012 |
4 | 10303033331100013132313 |
5 | 10231412444324323224 |
6 | 112523351013302435 |
7 | 4306302633221651 |
oct | 463177520073667 |
9 | 82673855615735 |
10 | 21114013120439 |
11 | 6800447a688a8 |
12 | 2450054334a1b |
13 | ba2073312b45 |
14 | 52dcd08556d1 |
15 | 269355bac80e |
hex | 1333fd4077b7 |
21114013120439 has 2 divisors, whose sum is σ = 21114013120440. Its totient is φ = 21114013120438.
The previous prime is 21114013120411. The next prime is 21114013120457. The reversal of 21114013120439 is 93402131041112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21114013120439 - 232 = 21109718153143 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21114013120469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10557006560219 + 10557006560220.
It is an arithmetic number, because the mean of its divisors is an integer number (10557006560220).
Almost surely, 221114013120439 is an apocalyptic number.
21114013120439 is a deficient number, since it is larger than the sum of its proper divisors (1).
21114013120439 is an equidigital number, since it uses as much as digits as its factorization.
21114013120439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 32.
The spelling of 21114013120439 in words is "twenty-one trillion, one hundred fourteen billion, thirteen million, one hundred twenty thousand, four hundred thirty-nine".
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