Base | Representation |
---|---|
bin | 1100010010100011111… |
… | …1110000100010000101 |
3 | 202011222210102021201122 |
4 | 3010220333300202011 |
5 | 11424404121400010 |
6 | 240555200403325 |
7 | 21153163405451 |
oct | 3045077604205 |
9 | 664883367648 |
10 | 211141200005 |
11 | 815a978070a |
12 | 34b06916545 |
13 | 16bab584108 |
14 | a30da29661 |
15 | 575b605855 |
hex | 3128ff0885 |
211141200005 has 4 divisors (see below), whose sum is σ = 253369440012. Its totient is φ = 168912960000.
The previous prime is 211141199993. The next prime is 211141200037. The reversal of 211141200005 is 500002141112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 124469251204 + 86671948801 = 352802^2 + 294401^2 .
It is not a de Polignac number, because 211141200005 - 216 = 211141134469 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21114119996 + ... + 21114120005.
It is an arithmetic number, because the mean of its divisors is an integer number (63342360003).
Almost surely, 2211141200005 is an apocalyptic number.
It is an amenable number.
211141200005 is a deficient number, since it is larger than the sum of its proper divisors (42228240007).
211141200005 is an equidigital number, since it uses as much as digits as its factorization.
211141200005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42228240006.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 211141200005 its reverse (500002141112), we get a palindrome (711143341117).
The spelling of 211141200005 in words is "two hundred eleven billion, one hundred forty-one million, two hundred thousand, five".
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