21114201401 has 4 divisors (see below), whose sum is σ = 21795304704. Its totient is φ = 20433098100.

The previous prime is 21114201397. The next prime is 21114201403. The reversal of 21114201401 is 10410241112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21114201401 - 2² = 21114201397 is a prime.

It is a super-4 number, since 4×21114201401⁴ (a number of 42 digits) contains 4444 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 21114201401.

It is not an unprimeable number, because it can be changed into a prime (21114201403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 340551605 + ... + 340551666.

It is an arithmetic number, because the mean of its divisors is an integer number (5448826176).

Almost surely, 2^21114201401 is an apocalyptic number.

It is an amenable number.

21114201401 is a deficient number, since it is larger than the sum of its proper divisors (681103303).

21114201401 is an equidigital number, since it uses as much as digits as its factorization.

21114201401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 681103302.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 21114201401 its reverse (10410241112), we get a palindrome (31524442513).

The spelling of 21114201401 in words is "twenty-one billion, one hundred fourteen million, two hundred one thousand, four hundred one".