21114433121 has 4 divisors (see below), whose sum is σ = 21220536000. Its totient is φ = 21008330244.

The previous prime is 21114433117. The next prime is 21114433169. The reversal of 21114433121 is 12133441112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21114433121 - 2² = 21114433117 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21114433321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53051141 + ... + 53051538.

It is an arithmetic number, because the mean of its divisors is an integer number (5305134000).

Almost surely, 2^21114433121 is an apocalyptic number.

It is an amenable number.

21114433121 is a deficient number, since it is larger than the sum of its proper divisors (106102879).

21114433121 is a wasteful number, since it uses less digits than its factorization.

21114433121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106102878.

The product of its digits is 576, while the sum is 23.

Adding to 21114433121 its reverse (12133441112), we get a palindrome (33247874233).

The spelling of 21114433121 in words is "twenty-one billion, one hundred fourteen million, four hundred thirty-three thousand, one hundred twenty-one".