Base | Representation |
---|---|
bin | 1001100110100010101101… |
… | …01110000000111001110011 |
3 | 2202202121211111002201220012 |
4 | 10303101112232000321303 |
5 | 10231424033104130120 |
6 | 112524155553205135 |
7 | 4306355060463143 |
oct | 463212656007163 |
9 | 82677744081805 |
10 | 21115514130035 |
11 | 68010482785a6 |
12 | 24503b2b607ab |
13 | ba22522997c0 |
14 | 52ddd3d3c923 |
15 | 2693e28561c5 |
hex | 133456b80e73 |
21115514130035 has 16 divisors (see below), whose sum is σ = 27330179558304. Its totient is φ = 15568744637952.
The previous prime is 21115514130023. The next prime is 21115514130077. The reversal of 21115514130035 is 53003141551112.
It is a cyclic number.
It is not a de Polignac number, because 21115514130035 - 24 = 21115514130019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21115514129983 and 21115514130010.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 252566342 + ... + 252649931.
It is an arithmetic number, because the mean of its divisors is an integer number (1708136222394).
Almost surely, 221115514130035 is an apocalyptic number.
21115514130035 is a deficient number, since it is larger than the sum of its proper divisors (6214665428269).
21115514130035 is a wasteful number, since it uses less digits than its factorization.
21115514130035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 505216934.
The product of its (nonzero) digits is 9000, while the sum is 32.
Adding to 21115514130035 its reverse (53003141551112), we get a palindrome (74118655681147).
The spelling of 21115514130035 in words is "twenty-one trillion, one hundred fifteen billion, five hundred fourteen million, one hundred thirty thousand, thirty-five".
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