Base | Representation |
---|---|
bin | 11110101110101001010… |
… | …111101100111001010101 |
3 | 21110212120221121021110101 |
4 | 132232221113230321111 |
5 | 234044200122130140 |
6 | 4254031003254101 |
7 | 305364110064433 |
oct | 36565127547125 |
9 | 7425527537411 |
10 | 2111670505045 |
11 | 744610a49082 |
12 | 2a130a21a331 |
13 | 12418bb816aa |
14 | 742c387bd53 |
15 | 39de1a9e99a |
hex | 1eba95ece55 |
2111670505045 has 4 divisors (see below), whose sum is σ = 2534004606060. Its totient is φ = 1689336404032.
The previous prime is 2111670504971. The next prime is 2111670505069. The reversal of 2111670505045 is 5405050761112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1370793714481 + 740876790564 = 1170809^2 + 860742^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111670505045 - 27 = 2111670504917 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2111670504995 and 2111670505013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211167050500 + ... + 211167050509.
It is an arithmetic number, because the mean of its divisors is an integer number (633501151515).
Almost surely, 22111670505045 is an apocalyptic number.
It is an amenable number.
2111670505045 is a deficient number, since it is larger than the sum of its proper divisors (422334101015).
2111670505045 is an equidigital number, since it uses as much as digits as its factorization.
2111670505045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 422334101014.
The product of its (nonzero) digits is 42000, while the sum is 37.
The spelling of 2111670505045 in words is "two trillion, one hundred eleven billion, six hundred seventy million, five hundred five thousand, forty-five".
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