Base | Representation |
---|---|
bin | 10011101010110111… |
… | …010100111100011001 |
3 | 2000111220110102121012 |
4 | 103222313110330121 |
5 | 321223240211213 |
6 | 13411424023305 |
7 | 1345244042624 |
oct | 235267247431 |
9 | 60456412535 |
10 | 21120241433 |
11 | 8a58909a95 |
12 | 4115161b35 |
13 | 1cb77c48a5 |
14 | 1044db2dbb |
15 | 83929e4a8 |
hex | 4eadd4f19 |
21120241433 has 4 divisors (see below), whose sum is σ = 21569608320. Its totient is φ = 20670874548.
The previous prime is 21120241421. The next prime is 21120241459. The reversal of 21120241433 is 33414202112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21120241433 - 212 = 21120237337 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21120241399 and 21120241408.
It is not an unprimeable number, because it can be changed into a prime (21120241733) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224683373 + ... + 224683466.
It is an arithmetic number, because the mean of its divisors is an integer number (5392402080).
Almost surely, 221120241433 is an apocalyptic number.
It is an amenable number.
21120241433 is a deficient number, since it is larger than the sum of its proper divisors (449366887).
21120241433 is an equidigital number, since it uses as much as digits as its factorization.
21120241433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 449366886.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 21120241433 its reverse (33414202112), we get a palindrome (54534443545).
The spelling of 21120241433 in words is "twenty-one billion, one hundred twenty million, two hundred forty-one thousand, four hundred thirty-three".
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