Base | Representation |
---|---|
bin | 1100010010110011000… |
… | …0111001001110001101 |
3 | 202012011012100210200210 |
4 | 3010230300321032031 |
5 | 11430021312143201 |
6 | 241005335313033 |
7 | 21154561612041 |
oct | 3045460711615 |
9 | 665135323623 |
10 | 211204412301 |
11 | 81631425a83 |
12 | 34b23b1b779 |
13 | 16bbb6b723c |
14 | a3181a2021 |
15 | 5761e401d6 |
hex | 312cc3938d |
211204412301 has 8 divisors (see below), whose sum is σ = 291316430880. Its totient is φ = 135947667632.
The previous prime is 211204412291. The next prime is 211204412381. The reversal of 211204412301 is 103214402112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 211204412301 - 27 = 211204412173 is a prime.
It is a super-2 number, since 2×2112044123012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211204412381) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1213818375 + ... + 1213818548.
It is an arithmetic number, because the mean of its divisors is an integer number (36414553860).
Almost surely, 2211204412301 is an apocalyptic number.
It is an amenable number.
211204412301 is a deficient number, since it is larger than the sum of its proper divisors (80112018579).
211204412301 is a wasteful number, since it uses less digits than its factorization.
211204412301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2427636955.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 211204412301 its reverse (103214402112), we get a palindrome (314418814413).
The spelling of 211204412301 in words is "two hundred eleven billion, two hundred four million, four hundred twelve thousand, three hundred one".
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