Base | Representation |
---|---|
bin | 11110101111000011000… |
… | …010101011000011110001 |
3 | 21110220200222000212000120 |
4 | 132233003002223003301 |
5 | 234101040401400423 |
6 | 4254141430440453 |
7 | 305410556661252 |
oct | 36570302530361 |
9 | 7426628025016 |
10 | 2112101200113 |
11 | 744812079713 |
12 | 2a140a503129 |
13 | 12422a17c448 |
14 | 74324b52b29 |
15 | 39e197c7ee3 |
hex | 1ebc30ab0f1 |
2112101200113 has 8 divisors (see below), whose sum is σ = 2850064270368. Its totient is φ = 1391102798304.
The previous prime is 2112101200073. The next prime is 2112101200189. The reversal of 2112101200113 is 3110021012112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2112101200113 - 220 = 2112100151537 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2112101200092 and 2112101200101.
It is not an unprimeable number, because it can be changed into a prime (2112111200113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4241166820 + ... + 4241167317.
It is an arithmetic number, because the mean of its divisors is an integer number (356258033796).
Almost surely, 22112101200113 is an apocalyptic number.
It is an amenable number.
2112101200113 is a deficient number, since it is larger than the sum of its proper divisors (737963070255).
2112101200113 is an equidigital number, since it uses as much as digits as its factorization.
2112101200113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8482334223.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 2112101200113 its reverse (3110021012112), we get a palindrome (5222122212225).
The spelling of 2112101200113 in words is "two trillion, one hundred twelve billion, one hundred one million, two hundred thousand, one hundred thirteen".
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