Base | Representation |
---|---|
bin | 10011101010111010… |
… | …010001000110010001 |
3 | 2000111221220120202220 |
4 | 103222322101012101 |
5 | 321223434341423 |
6 | 13411452331253 |
7 | 1345253432535 |
oct | 235272210621 |
9 | 60457816686 |
10 | 21121012113 |
11 | 8a59296013 |
12 | 4115473b29 |
13 | 1cb7a04606 |
14 | 1045133bc5 |
15 | 8393a29e3 |
hex | 4eae91191 |
21121012113 has 8 divisors (see below), whose sum is σ = 28194136800. Its totient is φ = 14064281088.
The previous prime is 21121012103. The next prime is 21121012189. The reversal of 21121012113 is 31121012112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 21121012113 - 26 = 21121012049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21121012092 and 21121012101.
It is not an unprimeable number, because it can be changed into a prime (21121012103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4095408 + ... + 4100561.
It is an arithmetic number, because the mean of its divisors is an integer number (3524267100).
Almost surely, 221121012113 is an apocalyptic number.
It is an amenable number.
21121012113 is a deficient number, since it is larger than the sum of its proper divisors (7073124687).
21121012113 is an equidigital number, since it uses as much as digits as its factorization.
21121012113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8196831.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 21121012113 its reverse (31121012112), we get a palindrome (52242024225).
Subtracting 21121012113 from its reverse (31121012112), we obtain a palindrome (9999999999).
The spelling of 21121012113 in words is "twenty-one billion, one hundred twenty-one million, twelve thousand, one hundred thirteen".
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