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2112102113 = 11601319483
BaseRepresentation
bin111110111100100…
…0001111011100001
312110012021220102012
41331321001323201
513311144231423
6545325402305
7103224400052
oct17571017341
95405256365
102112102113
11994254640
124ab409395
13278767484
1416071a729
15c5658078
hex7de41ee1

2112102113 has 8 divisors (see below), whose sum is σ = 2307952416. Its totient is φ = 1916892000.

The previous prime is 2112102089. The next prime is 2112102131. The reversal of 2112102113 is 3112012112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2112102113 - 28 = 2112101857 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2112102133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 153131 + ... + 166352.

It is an arithmetic number, because the mean of its divisors is an integer number (288494052).

Almost surely, 22112102113 is an apocalyptic number.

It is an amenable number.

2112102113 is a deficient number, since it is larger than the sum of its proper divisors (195850303).

2112102113 is a wasteful number, since it uses less digits than its factorization.

2112102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 320095.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 2112102113 is about 45957.6121333561. The cubic root of 2112102113 is about 1283.0344091243.

Adding to 2112102113 its reverse (3112012112), we get a palindrome (5224114225).

Subtracting 2112102113 from its reverse (3112012112), we obtain a palindrome (999909999).

The spelling of 2112102113 in words is "two billion, one hundred twelve million, one hundred two thousand, one hundred thirteen".

Divisors: 1 11 601 6611 319483 3514313 192009283 2112102113