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2112104001345 = 351310831302571
BaseRepresentation
bin11110101111000011001…
…101010110111101000001
321110220201011022011120220
4132233003031112331001
5234101042111020340
64254142010453253
7305410622536152
oct36570315267501
97426634264526
102112104001345
11744813712288
122a140b434229
1312422a920490
1474325281929
1539e19b7ced0
hex1ebc3356f41

2112104001345 has 16 divisors (see below), whose sum is σ = 3639317664192. Its totient is φ = 1039805046720.

The previous prime is 2112104001323. The next prime is 2112104001349. The reversal of 2112104001345 is 5431004012112.

It is not a de Polignac number, because 2112104001345 - 25 = 2112104001313 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2112104001349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5415651091 + ... + 5415651480.

It is an arithmetic number, because the mean of its divisors is an integer number (227457354012).

Almost surely, 22112104001345 is an apocalyptic number.

It is an amenable number.

2112104001345 is a deficient number, since it is larger than the sum of its proper divisors (1527213662847).

2112104001345 is a wasteful number, since it uses less digits than its factorization.

2112104001345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10831302592.

The product of its (nonzero) digits is 960, while the sum is 24.

Adding to 2112104001345 its reverse (5431004012112), we get a palindrome (7543108013457).

The spelling of 2112104001345 in words is "two trillion, one hundred twelve billion, one hundred four million, one thousand, three hundred forty-five".

Divisors: 1 3 5 13 15 39 65 195 10831302571 32493907713 54156512855 140806933423 162469538565 422420800269 704034667115 2112104001345