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2112110113 = 10919377157
BaseRepresentation
bin111110111100100…
…0011111000100001
312110012022022101111
41331321003320201
513311200010423
6545325503321
7103224432301
oct17571037041
95405268344
102112110113
1199425a653
124ab411b41
1327876acc9
1416071d601
15c565a60d
hex7de43e21

2112110113 has 4 divisors (see below), whose sum is σ = 2131487380. Its totient is φ = 2092732848.

The previous prime is 2112110083. The next prime is 2112110123. The reversal of 2112110113 is 3110112112.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 874266624 + 1237843489 = 29568^2 + 35183^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2112110113 is a prime.

It is a super-2 number, since 2×21121101132 = 8922018258873745538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2112110093 and 2112110102.

It is not an unprimeable number, because it can be changed into a prime (2112110123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9688470 + ... + 9688687.

It is an arithmetic number, because the mean of its divisors is an integer number (532871845).

Almost surely, 22112110113 is an apocalyptic number.

It is an amenable number.

2112110113 is a deficient number, since it is larger than the sum of its proper divisors (19377267).

2112110113 is a wasteful number, since it uses less digits than its factorization.

2112110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19377266.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 2112110113 is about 45957.6991699976. The cubic root of 2112110113 is about 1283.0360290368.

Adding to 2112110113 its reverse (3110112112), we get a palindrome (5222222225).

It can be divided in two parts, 2112 and 110113, that added together give a square (112225 = 3352).

The spelling of 2112110113 in words is "two billion, one hundred twelve million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 109 19377157 2112110113