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211211102121 = 370403700707
BaseRepresentation
bin1100010010110100101…
…0011010011110101001
3202012011122221200101220
43010231022122132221
511430030020231441
6241010134532253
721155002513635
oct3045512323651
9665148850356
10211211102121
1181635185158
1234b26207089
1316bbcbba206
14a319023dc5
155762812466
hex312d29a7a9

211211102121 has 4 divisors (see below), whose sum is σ = 281614802832. Its totient is φ = 140807401412.

The previous prime is 211211102119. The next prime is 211211102209. The reversal of 211211102121 is 121201112112.

It is a happy number.

211211102121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211211102121 - 21 = 211211102119 is a prime.

It is a super-2 number, since 2×2112111021212 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211211102121.

It is not an unprimeable number, because it can be changed into a prime (211211102111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35201850351 + ... + 35201850356.

It is an arithmetic number, because the mean of its divisors is an integer number (70403700708).

Almost surely, 2211211102121 is an apocalyptic number.

It is an amenable number.

211211102121 is a deficient number, since it is larger than the sum of its proper divisors (70403700711).

211211102121 is an equidigital number, since it uses as much as digits as its factorization.

211211102121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70403700710.

The product of its (nonzero) digits is 16, while the sum is 15.

Adding to 211211102121 its reverse (121201112112), we get a palindrome (332412214233).

Subtracting from 211211102121 its reverse (121201112112), we obtain a palindrome (90009990009).

The spelling of 211211102121 in words is "two hundred eleven billion, two hundred eleven million, one hundred two thousand, one hundred twenty-one".

Divisors: 1 3 70403700707 211211102121