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21121121133002 = 211960050960591
BaseRepresentation
bin1001100110101101001001…
…11011000010000111001010
32202210011022020122222222202
410303112210323002013022
510232022024002224002
6112530524210520202
74306644033304442
oct463264473020712
982704266588882
1021121121133002
116803465286950
1224514b8896062
13ba2936b06637
145303a688b122
1526961ec10502
hex1335a4ec21ca

21121121133002 has 8 divisors (see below), whose sum is σ = 34561834581312. Its totient is φ = 9600509605900.

The previous prime is 21121121132999. The next prime is 21121121133059. The reversal of 21121121133002 is 20033112112112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×211211211330022 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 480025480274 + ... + 480025480317.

It is an arithmetic number, because the mean of its divisors is an integer number (4320229322664).

Almost surely, 221121121133002 is an apocalyptic number.

21121121133002 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

21121121133002 is a deficient number, since it is larger than the sum of its proper divisors (13440713448310).

21121121133002 is a wasteful number, since it uses less digits than its factorization.

21121121133002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 960050960604.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 21121121133002 its reverse (20033112112112), we get a palindrome (41154233245114).

The spelling of 21121121133002 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred twenty-one million, one hundred thirty-three thousand, two".

Divisors: 1 2 11 22 960050960591 1920101921182 10560560566501 21121121133002