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211211213002 = 2105605606501
BaseRepresentation
bin1100010010110100101…
…0110101100011001010
3202012011200011022111121
43010231022311203022
511430030032304002
6241010141145454
721155003455126
oct3045512654312
9665150138447
10211211213002
1181635250499
1234b2625b28a
1316bbcc2881a
14a319052586
155762835237
hex312d2b58ca

211211213002 has 4 divisors (see below), whose sum is σ = 316816819506. Its totient is φ = 105605606500.

The previous prime is 211211212997. The next prime is 211211213011. The reversal of 211211213002 is 200312112112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 184538117241 + 26673095761 = 429579^2 + 163319^2 .

It is a super-2 number, since 2×2112112130022 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52802803249 + ... + 52802803252.

Almost surely, 2211211213002 is an apocalyptic number.

211211213002 is a deficient number, since it is larger than the sum of its proper divisors (105605606504).

211211213002 is a wasteful number, since it uses less digits than its factorization.

211211213002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105605606503.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 211211213002 its reverse (200312112112), we get a palindrome (411523325114).

The spelling of 211211213002 in words is "two hundred eleven billion, two hundred eleven million, two hundred thirteen thousand, two".

Divisors: 1 2 105605606501 211211213002