Base | Representation |
---|---|
bin | 11110101111000100001… |
… | …111011001010010010001 |
3 | 21110220202100212122220010 |
4 | 132233010033121102101 |
5 | 234101111023444101 |
6 | 4254143425505133 |
7 | 305411222635542 |
oct | 36570417312221 |
9 | 7426670778803 |
10 | 2112121312401 |
11 | 744822466341 |
12 | 2a14151a21a9 |
13 | 1242313a19c9 |
14 | 743276aa4c9 |
15 | 39e1b44c2d6 |
hex | 1ebc43d9491 |
2112121312401 has 16 divisors (see below), whose sum is σ = 2939279736960. Its totient is φ = 1347817860480.
The previous prime is 2112121312373. The next prime is 2112121312421. The reversal of 2112121312401 is 1042131212112.
It is not a de Polignac number, because 2112121312401 - 26 = 2112121312337 is a prime.
It is a super-2 number, since 2×21121213124012 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2112121312421) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 161990821 + ... + 162003858.
It is an arithmetic number, because the mean of its divisors is an integer number (183704983560).
Almost surely, 22112121312401 is an apocalyptic number.
It is an amenable number.
2112121312401 is a deficient number, since it is larger than the sum of its proper divisors (827158424559).
2112121312401 is a wasteful number, since it uses less digits than its factorization.
2112121312401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 323994776.
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 2112121312401 its reverse (1042131212112), we get a palindrome (3154252524513).
The spelling of 2112121312401 in words is "two trillion, one hundred twelve billion, one hundred twenty-one million, three hundred twelve thousand, four hundred one".
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