Base | Representation |
---|---|
bin | 11110101111000100011… |
… | …010111101001100111111 |
3 | 21110220202120120122020100 |
4 | 132233010122331030333 |
5 | 234101112312434403 |
6 | 4254144014452143 |
7 | 305411260460445 |
oct | 36570432751477 |
9 | 7426676518210 |
10 | 2112124343103 |
11 | 744824146355 |
12 | 2a1416204053 |
13 | 124231bc3318 |
14 | 74327c58b95 |
15 | 39e1b84a2a3 |
hex | 1ebc46bd33f |
2112124343103 has 12 divisors (see below), whose sum is σ = 3050861447088. Its totient is φ = 1408075892160.
The previous prime is 2112124343083. The next prime is 2112124343107. The reversal of 2112124343103 is 3013434212112.
2112124343103 is a `hidden beast` number, since 2 + 1 + 1 + 212 + 4 + 343 + 103 = 666.
It is not a de Polignac number, because 2112124343103 - 29 = 2112124342591 is a prime.
It is a super-2 number, since 2×21121243431032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2112124343107) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1868926 + ... + 2777972.
It is an arithmetic number, because the mean of its divisors is an integer number (254238453924).
Almost surely, 22112124343103 is an apocalyptic number.
2112124343103 is a deficient number, since it is larger than the sum of its proper divisors (938737103985).
2112124343103 is a wasteful number, since it uses less digits than its factorization.
2112124343103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1167214 (or 1167211 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 2112124343103 its reverse (3013434212112), we get a palindrome (5125558555215).
The spelling of 2112124343103 in words is "two trillion, one hundred twelve billion, one hundred twenty-four million, three hundred forty-three thousand, one hundred three".
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