211212534212401 has 4 divisors (see below), whose sum is σ = 211728946276900. Its totient is φ = 210696122147904.

The previous prime is 211212534212377. The next prime is 211212534212447. The reversal of 211212534212401 is 104212435212112.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 129395516296225 + 81817017916176 = 11375215^2 + 9045276^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211212534212401 is a prime.

It is a super-2 number, since 2×211212534212401² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211212534218401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258206031636 + ... + 258206032453.

It is an arithmetic number, because the mean of its divisors is an integer number (52932236569225).

Almost surely, 2^{211212534212401} is an apocalyptic number.

It is an amenable number.

211212534212401 is a deficient number, since it is larger than the sum of its proper divisors (516412064499).

211212534212401 is an equidigital number, since it uses as much as digits as its factorization.

211212534212401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 516412064498.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 211212534212401 its reverse (104212435212112), we get a palindrome (315424969424513).

The spelling of 211212534212401 in words is "two hundred eleven trillion, two hundred twelve billion, five hundred thirty-four million, two hundred twelve thousand, four hundred one".