Base | Representation |
---|---|
bin | 1100010010110101001… |
… | …0000111010111111111 |
3 | 202012011210202020211001 |
4 | 3010231102013113333 |
5 | 11430031024333043 |
6 | 241010250111131 |
7 | 21155025622642 |
oct | 3045522072777 |
9 | 665153666731 |
10 | 211213121023 |
11 | 81636333a73 |
12 | 34b26a1b4a7 |
13 | 16bc0446128 |
14 | a3193cba59 |
15 | 5762ab074d |
hex | 312d4875ff |
211213121023 has 4 divisors (see below), whose sum is σ = 211263069240. Its totient is φ = 211163172808.
The previous prime is 211213120991. The next prime is 211213121027. The reversal of 211213121023 is 320121312112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211213121023 - 25 = 211213120991 is a prime.
It is a super-2 number, since 2×2112131210232 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211213121027) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24967765 + ... + 24976222.
It is an arithmetic number, because the mean of its divisors is an integer number (52815767310).
Almost surely, 2211213121023 is an apocalyptic number.
211213121023 is a deficient number, since it is larger than the sum of its proper divisors (49948217).
211213121023 is an equidigital number, since it uses as much as digits as its factorization.
211213121023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49948216.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 211213121023 its reverse (320121312112), we get a palindrome (531334433135).
The spelling of 211213121023 in words is "two hundred eleven billion, two hundred thirteen million, one hundred twenty-one thousand, twenty-three".
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