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2112132021000 = 2335323316911429
BaseRepresentation
bin11110101111000100111…
…000001111101100001000
321110220210010000201022220
4132233010320033230020
5234101121244133000
64254144451214040
7305411412646131
oct36570470175410
97426703021286
102112132021000
1174482850a921
122a14188a7320
13124233680c61
1474328c96c88
1539e1c3651a0
hex1ebc4e0fb08

2112132021000 has 512 divisors, whose sum is σ = 7113432268800. Its totient is φ = 520248960000.

The previous prime is 2112132020983. The next prime is 2112132021017. The reversal of 2112132021000 is 1202312112.

It is an interprime number because it is at equal distance from previous prime (2112132020983) and next prime (2112132021017).

It is a super-2 number, since 2×21121320210002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1478048286 + ... + 1478049714.

It is an arithmetic number, because the mean of its divisors is an integer number (13893422400).

Almost surely, 22112132021000 is an apocalyptic number.

2112132021000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2112132021000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3556716134400).

2112132021000 is an abundant number, since it is smaller than the sum of its proper divisors (5001300247800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2112132021000 is a wasteful number, since it uses less digits than its factorization.

2112132021000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2198 (or 2184 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 2112132021000 its reverse (1202312112), we get a palindrome (2113334333112).

The spelling of 2112132021000 in words is "two trillion, one hundred twelve billion, one hundred thirty-two million, twenty-one thousand".