Base | Representation |
---|---|
bin | 11110101111000100111… |
… | …000101010010101010011 |
3 | 21110220210010020021000210 |
4 | 132233010320222111103 |
5 | 234101121311131011 |
6 | 4254144453415203 |
7 | 305411413612242 |
oct | 36570470522523 |
9 | 7426703207023 |
10 | 2112132130131 |
11 | 744828584911 |
12 | 2a141893a503 |
13 | 1242336bb82a |
14 | 74328cc4959 |
15 | 39e1c3876a6 |
hex | 1ebc4e2a553 |
2112132130131 has 32 divisors (see below), whose sum is σ = 2863509926400. Its totient is φ = 1384531948800.
The previous prime is 2112132130111. The next prime is 2112132130153. The reversal of 2112132130131 is 1310312312112.
It is not a de Polignac number, because 2112132130131 - 25 = 2112132130099 is a prime.
It is a super-2 number, since 2×21121321301312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2112132130098 and 2112132130107.
It is not an unprimeable number, because it can be changed into a prime (2112132130111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 161237220 + ... + 161250318.
It is an arithmetic number, because the mean of its divisors is an integer number (89484685200).
Almost surely, 22112132130131 is an apocalyptic number.
2112132130131 is a deficient number, since it is larger than the sum of its proper divisors (751377796269).
2112132130131 is a wasteful number, since it uses less digits than its factorization.
2112132130131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15147.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 2112132130131 its reverse (1310312312112), we get a palindrome (3422444442243).
The spelling of 2112132130131 in words is "two trillion, one hundred twelve billion, one hundred thirty-two million, one hundred thirty thousand, one hundred thirty-one".
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