Base | Representation |
---|---|
bin | 10011101010111011… |
… | …110101011111100111 |
3 | 2000111222200110212100 |
4 | 103222323311133213 |
5 | 321224041021320 |
6 | 13411505223143 |
7 | 1345260064455 |
oct | 235273653747 |
9 | 60458613770 |
10 | 21121423335 |
11 | 8a59546a71 |
12 | 4115631ab3 |
13 | 1cb7b1983c |
14 | 10451dd9d5 |
15 | 839434790 |
hex | 4eaef57e7 |
21121423335 has 12 divisors (see below), whose sum is σ = 36610467192. Its totient is φ = 11264759088.
The previous prime is 21121423327. The next prime is 21121423447. The reversal of 21121423335 is 53332412112.
21121423335 is a `hidden beast` number, since 211 + 21 + 423 + 3 + 3 + 5 = 666.
It is not a de Polignac number, because 21121423335 - 23 = 21121423327 is a prime.
It is a super-2 number, since 2×211214233352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21121423299 and 21121423308.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 234682437 + ... + 234682526.
It is an arithmetic number, because the mean of its divisors is an integer number (3050872266).
Almost surely, 221121423335 is an apocalyptic number.
21121423335 is a deficient number, since it is larger than the sum of its proper divisors (15489043857).
21121423335 is a wasteful number, since it uses less digits than its factorization.
21121423335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 469364974 (or 469364971 counting only the distinct ones).
The product of its digits is 4320, while the sum is 27.
Adding to 21121423335 its reverse (53332412112), we get a palindrome (74453835447).
The spelling of 21121423335 in words is "twenty-one billion, one hundred twenty-one million, four hundred twenty-three thousand, three hundred thirty-five".
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