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2112152632111 = 17563112026081
BaseRepresentation
bin11110101111000110000…
…110110111101100101111
321110220211112210212110101
4132233012012313230233
5234101142033211421
64254150505051531
7305412053101624
oct36570606675457
97426745725411
102112152632111
117448391082a5
122a1423786ba7
13124237a19592
147432b90034b
1539e1e087191
hex1ebc61b7b2f

2112152632111 has 4 divisors (see below), whose sum is σ = 2112164833824. Its totient is φ = 2112140430400.

The previous prime is 2112152632067. The next prime is 2112152632127. The reversal of 2112152632111 is 1112362512112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2112152632111 - 215 = 2112152599343 is a prime.

It is a super-2 number, since 2×21121526321112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2112152632111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2112152632181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5837410 + ... + 6188671.

It is an arithmetic number, because the mean of its divisors is an integer number (528041208456).

Almost surely, 22112152632111 is an apocalyptic number.

2112152632111 is a deficient number, since it is larger than the sum of its proper divisors (12201713).

2112152632111 is a wasteful number, since it uses less digits than its factorization.

2112152632111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12201712.

The product of its digits is 1440, while the sum is 28.

The spelling of 2112152632111 in words is "two trillion, one hundred twelve billion, one hundred fifty-two million, six hundred thirty-two thousand, one hundred eleven".

Divisors: 1 175631 12026081 2112152632111