Base | Representation |
---|---|
bin | 1001100110101110110010… |
… | …10101010101011111001111 |
3 | 2202210020120112020121000102 |
4 | 10303113121111111133033 |
5 | 10232030324103141333 |
6 | 112531151341321315 |
7 | 4310004601312442 |
oct | 463273125253717 |
9 | 82706515217012 |
10 | 21122000443343 |
11 | 6803876667808 |
12 | 245170326623b |
13 | ba2a47037a07 |
14 | 53044b57d659 |
15 | 269672001ae8 |
hex | 1335d95557cf |
21122000443343 has 4 divisors (see below), whose sum is σ = 21122025283368. Its totient is φ = 21121975603320.
The previous prime is 21122000443331. The next prime is 21122000443363. The reversal of 21122000443343 is 34334400022112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21122000443343 is a prime.
It is a super-2 number, since 2×211220004433432 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21122000443363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11097596 + ... + 12860817.
It is an arithmetic number, because the mean of its divisors is an integer number (5280506320842).
Almost surely, 221122000443343 is an apocalyptic number.
21122000443343 is a deficient number, since it is larger than the sum of its proper divisors (24840025).
21122000443343 is an equidigital number, since it uses as much as digits as its factorization.
21122000443343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24840024.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 21122000443343 its reverse (34334400022112), we get a palindrome (55456400465455).
The spelling of 21122000443343 in words is "twenty-one trillion, one hundred twenty-two billion, four hundred forty-three thousand, three hundred forty-three".
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