Base | Representation |
---|---|
bin | 10011101010111110… |
… | …000101110010000101 |
3 | 2000112000210111120110 |
4 | 103222332011302011 |
5 | 321224213424331 |
6 | 13411530023233 |
7 | 1345265105511 |
oct | 235276056205 |
9 | 60460714513 |
10 | 21122014341 |
11 | 8a5990aaaa |
12 | 4115877b19 |
13 | 1cb7c9584c |
14 | 1045315141 |
15 | 8394ee946 |
hex | 4eaf85c85 |
21122014341 has 8 divisors (see below), whose sum is σ = 28167097504. Its totient is φ = 14079137040.
The previous prime is 21122014313. The next prime is 21122014343. The reversal of 21122014341 is 14341022112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 21122014341 - 213 = 21122006149 is a prime.
It is a super-3 number, since 3×211220143413 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21122014343) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 528991 + ... + 567516.
It is an arithmetic number, because the mean of its divisors is an integer number (3520887188).
Almost surely, 221122014341 is an apocalyptic number.
It is an amenable number.
21122014341 is a deficient number, since it is larger than the sum of its proper divisors (7045083163).
21122014341 is a wasteful number, since it uses less digits than its factorization.
21122014341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1102931.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 21122014341 its reverse (14341022112), we get a palindrome (35463036453).
The spelling of 21122014341 in words is "twenty-one billion, one hundred twenty-two million, fourteen thousand, three hundred forty-one".
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