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21122014341 = 364211096507
BaseRepresentation
bin10011101010111110…
…000101110010000101
32000112000210111120110
4103222332011302011
5321224213424331
613411530023233
71345265105511
oct235276056205
960460714513
1021122014341
118a5990aaaa
124115877b19
131cb7c9584c
141045315141
158394ee946
hex4eaf85c85

21122014341 has 8 divisors (see below), whose sum is σ = 28167097504. Its totient is φ = 14079137040.

The previous prime is 21122014313. The next prime is 21122014343. The reversal of 21122014341 is 14341022112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 21122014341 - 213 = 21122006149 is a prime.

It is a super-3 number, since 3×211220143413 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21122014343) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 528991 + ... + 567516.

It is an arithmetic number, because the mean of its divisors is an integer number (3520887188).

Almost surely, 221122014341 is an apocalyptic number.

It is an amenable number.

21122014341 is a deficient number, since it is larger than the sum of its proper divisors (7045083163).

21122014341 is a wasteful number, since it uses less digits than its factorization.

21122014341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1102931.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 21122014341 its reverse (14341022112), we get a palindrome (35463036453).

The spelling of 21122014341 in words is "twenty-one billion, one hundred twenty-two million, fourteen thousand, three hundred forty-one".

Divisors: 1 3 6421 19263 1096507 3289521 7040671447 21122014341