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2112202111402 = 21056101055701
BaseRepresentation
bin11110101111001001000…
…011100111100110101010
321110220221222220200021201
4132233021003213212222
5234101242220031102
64254155433354414
7305413223500255
oct36571103474652
97426858820251
102112202111402
11744864032879
122a1438268a0a
13124245051976
147433430009c
1539e235ac987
hex1ebc90e79aa

2112202111402 has 4 divisors (see below), whose sum is σ = 3168303167106. Its totient is φ = 1056101055700.

The previous prime is 2112202111399. The next prime is 2112202111421. The reversal of 2112202111402 is 2041112022112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1698098278321 + 414103833081 = 1303111^2 + 643509^2 .

It is a super-2 number, since 2×21122021114022 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2112202111402.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 528050527849 + ... + 528050527852.

Almost surely, 22112202111402 is an apocalyptic number.

2112202111402 is a deficient number, since it is larger than the sum of its proper divisors (1056101055704).

2112202111402 is a wasteful number, since it uses less digits than its factorization.

2112202111402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1056101055703.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 2112202111402 its reverse (2041112022112), we get a palindrome (4153314133514).

The spelling of 2112202111402 in words is "two trillion, one hundred twelve billion, two hundred two million, one hundred eleven thousand, four hundred two".

Divisors: 1 2 1056101055701 2112202111402