Base | Representation |
---|---|
bin | 1100010010110111000… |
… | …0010101100011110001 |
3 | 202012012100122202022221 |
4 | 3010231300111203301 |
5 | 11430040041342231 |
6 | 241011132001041 |
7 | 21155153150242 |
oct | 3045560254361 |
9 | 665170582287 |
10 | 211221043441 |
11 | 8163a855221 |
12 | 34b29600181 |
13 | 16bc1c8b155 |
14 | a31a490cc9 |
15 | 5763627d11 |
hex | 312dc158f1 |
211221043441 has 4 divisors (see below), whose sum is σ = 212168223232. Its totient is φ = 210273863652.
The previous prime is 211221043433. The next prime is 211221043463. The reversal of 211221043441 is 144340122112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 211221043441 - 23 = 211221043433 is a prime.
It is a super-2 number, since 2×2112210434412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211221040441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 473589561 + ... + 473590006.
It is an arithmetic number, because the mean of its divisors is an integer number (53042055808).
Almost surely, 2211221043441 is an apocalyptic number.
It is an amenable number.
211221043441 is a deficient number, since it is larger than the sum of its proper divisors (947179791).
211221043441 is an equidigital number, since it uses as much as digits as its factorization.
211221043441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 947179790.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 211221043441 its reverse (144340122112), we get a palindrome (355561165553).
The spelling of 211221043441 in words is "two hundred eleven billion, two hundred twenty-one million, forty-three thousand, four hundred forty-one".
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