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211222022103 = 32214331094999
BaseRepresentation
bin1100010010110111010…
…0000100011111010111
3202012012102111110210200
43010231310010133113
511430040314201403
6241011204551543
721155164364421
oct3045564043727
9665172443720
10211222022103
1181640363534
1234b299b25b3
1316bc2241741
14a31a667811
15576376cca3
hex312dd047d7

211222022103 has 12 divisors (see below), whose sum is σ = 305112990000. Its totient is φ = 140807982816.

The previous prime is 211222022041. The next prime is 211222022111. The reversal of 211222022103 is 301220222112.

It is not a de Polignac number, because 211222022103 - 229 = 210685151191 is a prime.

It is a super-2 number, since 2×2112220221032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211222022113) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 354603 + ... + 740396.

It is an arithmetic number, because the mean of its divisors is an integer number (25426082500).

Almost surely, 2211222022103 is an apocalyptic number.

211222022103 is a deficient number, since it is larger than the sum of its proper divisors (93890967897).

211222022103 is a wasteful number, since it uses less digits than its factorization.

211222022103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1116438 (or 1116435 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 18.

Adding to 211222022103 its reverse (301220222112), we get a palindrome (512442244215).

Subtracting 211222022103 from its reverse (301220222112), we obtain a square (89998200009 = 2999972).

The spelling of 211222022103 in words is "two hundred eleven billion, two hundred twenty-two million, twenty-two thousand, one hundred three".

Divisors: 1 3 9 21433 64299 192897 1094999 3284997 9854991 23469113567 70407340701 211222022103