Base | Representation |
---|---|
bin | 1100010010111001101… |
… | …0101000111111111111 |
3 | 202012020010112011111202 |
4 | 3010232122220333333 |
5 | 11430100411224434 |
6 | 241012205410115 |
7 | 21155346335540 |
oct | 3045632507777 |
9 | 665203464452 |
10 | 211232133119 |
11 | 8164603a047 |
12 | 34b3126993b |
13 | 16bc43719a7 |
14 | a31bb3a4c7 |
15 | 57645b8a7e |
hex | 312e6a8fff |
211232133119 has 4 divisors (see below), whose sum is σ = 241408152144. Its totient is φ = 181056114096.
The previous prime is 211232133109. The next prime is 211232133139. The reversal of 211232133119 is 911331232112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211232133119 - 212 = 211232129023 is a prime.
It is a super-2 number, since 2×2112321331192 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 211232133091 and 211232133100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211232133109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15088009502 + ... + 15088009515.
It is an arithmetic number, because the mean of its divisors is an integer number (60352038036).
Almost surely, 2211232133119 is an apocalyptic number.
211232133119 is a deficient number, since it is larger than the sum of its proper divisors (30176019025).
211232133119 is an equidigital number, since it uses as much as digits as its factorization.
211232133119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30176019024.
The product of its digits is 1944, while the sum is 29.
The spelling of 211232133119 in words is "two hundred eleven billion, two hundred thirty-two million, one hundred thirty-three thousand, one hundred nineteen".
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