Base | Representation |
---|---|
bin | 11110101111010000001… |
… | …101110001001000110011 |
3 | 21110221021100220102212221 |
4 | 132233100031301020303 |
5 | 234102013441244103 |
6 | 4254215403501511 |
7 | 305416212362044 |
oct | 36572015611063 |
9 | 7427240812787 |
10 | 2112322212403 |
11 | 7449159034a7 |
12 | 2a1470527897 |
13 | 124263bb2850 |
14 | 743462448cb |
15 | 39e2ddd31bd |
hex | 1ebd0371233 |
2112322212403 has 8 divisors (see below), whose sum is σ = 2274952851248. Its totient is φ = 1949712189984.
The previous prime is 2112322212389. The next prime is 2112322212421. The reversal of 2112322212403 is 3042122232112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2112322212403 - 233 = 2103732277811 is a prime.
It is a super-2 number, since 2×21123222124032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2112322212493) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4940976 + ... + 5351437.
It is an arithmetic number, because the mean of its divisors is an integer number (284369106406).
Almost surely, 22112322212403 is an apocalyptic number.
2112322212403 is a deficient number, since it is larger than the sum of its proper divisors (162630638845).
2112322212403 is a wasteful number, since it uses less digits than its factorization.
2112322212403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10308213.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2112322212403 its reverse (3042122232112), we get a palindrome (5154444444515).
The spelling of 2112322212403 in words is "two trillion, one hundred twelve billion, three hundred twenty-two million, two hundred twelve thousand, four hundred three".
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