Base | Representation |
---|---|
bin | 11110101111010000110… |
… | …111011101100100100111 |
3 | 21110221022010110201220100 |
4 | 132233100313131210213 |
5 | 234102024241023221 |
6 | 4254220434035143 |
7 | 305416404313500 |
oct | 36572067354447 |
9 | 7427263421810 |
10 | 2112333142311 |
11 | 744920a99287 |
12 | 2a1474118ab3 |
13 | 12426623b752 |
14 | 7434788bba7 |
15 | 39e2ed41926 |
hex | 1ebd0ddd927 |
2112333142311 has 72 divisors (see below), whose sum is σ = 3615575218944. Its totient is φ = 1184639813280.
The previous prime is 2112333142303. The next prime is 2112333142321. The reversal of 2112333142311 is 1132413332112.
2112333142311 is a `hidden beast` number, since 2 + 1 + 1 + 2 + 33 + 314 + 2 + 311 = 666.
It is not a de Polignac number, because 2112333142311 - 23 = 2112333142303 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2112333142321) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 7875336 + ... + 8139138.
Almost surely, 22112333142311 is an apocalyptic number.
2112333142311 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2112333142311 is a deficient number, since it is larger than the sum of its proper divisors (1503242076633).
2112333142311 is a wasteful number, since it uses less digits than its factorization.
2112333142311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 264161 (or 264151 counting only the distinct ones).
The product of its digits is 2592, while the sum is 27.
Adding to 2112333142311 its reverse (1132413332112), we get a palindrome (3244746474423).
The spelling of 2112333142311 in words is "two trillion, one hundred twelve billion, three hundred thirty-three million, one hundred forty-two thousand, three hundred eleven".
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