Base | Representation |
---|---|
bin | 110000000001111000010101… |
… | …101110010011100001101101 |
3 | 1000200220220121102111101202222 |
4 | 300001320111232103201231 |
5 | 210141340143134341023 |
6 | 2025132120234125125 |
7 | 62331154161551063 |
oct | 6001702556234155 |
9 | 1020826542441688 |
10 | 211235446012013 |
11 | 613404a4416965 |
12 | 1b836a175807a5 |
13 | 90b35564574b7 |
14 | 3a23bc8ac8033 |
15 | 1964aba99ecc8 |
hex | c01e15b9386d |
211235446012013 has 4 divisors (see below), whose sum is σ = 211235980867968. Its totient is φ = 211234911156060.
The previous prime is 211235446011979. The next prime is 211235446012027. The reversal of 211235446012013 is 310210644532112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211235446012013 - 226 = 211235378903149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211235446912013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 266835131 + ... + 267625592.
It is an arithmetic number, because the mean of its divisors is an integer number (52808995216992).
Almost surely, 2211235446012013 is an apocalyptic number.
It is an amenable number.
211235446012013 is a deficient number, since it is larger than the sum of its proper divisors (534855955).
211235446012013 is an equidigital number, since it uses as much as digits as its factorization.
211235446012013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 534855954.
The product of its (nonzero) digits is 34560, while the sum is 35.
The spelling of 211235446012013 in words is "two hundred eleven trillion, two hundred thirty-five billion, four hundred forty-six million, twelve thousand, thirteen".
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