2112401443131 has 12 divisors (see below), whose sum is σ = 3487138890352. Its totient is φ = 1207086538896.

The previous prime is 2112401443129. The next prime is 2112401443177. The reversal of 2112401443131 is 1313441042112.

It is a happy number.

2112401443131 is a `hidden beast` number, since 211 + 2 + 4 + 0 + 1 + 443 + 1 + 3 + 1 = 666.

It is not a de Polignac number, because 2112401443131 - 2¹ = 2112401443129 is a prime.

It is a super-4 number, since 4×2112401443131⁴ (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2112401443095 and 2112401443104.

It is not an unprimeable number, because it can be changed into a prime (2112401443121) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 16765090756 + ... + 16765090881.

Almost surely, 2^{2112401443131} is an apocalyptic number.

2112401443131 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

2112401443131 is a deficient number, since it is larger than the sum of its proper divisors (1374737447221).

2112401443131 is a wasteful number, since it uses less digits than its factorization.

2112401443131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33530181650 (or 33530181647 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 2112401443131 its reverse (1313441042112), we get a palindrome (3425842485243).

The spelling of 2112401443131 in words is "two trillion, one hundred twelve billion, four hundred one million, four hundred forty-three thousand, one hundred thirty-one".