Base | Representation |
---|---|
bin | 11110101111010100111… |
… | …111010100111110010001 |
3 | 21110221110221121222101121 |
4 | 132233110333110332101 |
5 | 234102144443004410 |
6 | 4254231344402241 |
7 | 305421204254560 |
oct | 36572477247621 |
9 | 7427427558347 |
10 | 2112402313105 |
11 | 744957043327 |
12 | 2a1493316381 |
13 | 124277679a06 |
14 | 74352b35bd7 |
15 | 39e35e569da |
hex | 1ebd4fd4f91 |
2112402313105 has 16 divisors (see below), whose sum is σ = 2937811832064. Its totient is φ = 1428102970560.
The previous prime is 2112402312997. The next prime is 2112402313121. The reversal of 2112402313105 is 5013132042112.
It is not a de Polignac number, because 2112402313105 - 215 = 2112402280337 is a prime.
It is a super-2 number, since 2×21124023131052 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2112402313105.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 425028162 + ... + 425033131.
It is an arithmetic number, because the mean of its divisors is an integer number (183613239504).
Almost surely, 22112402313105 is an apocalyptic number.
It is an amenable number.
2112402313105 is a deficient number, since it is larger than the sum of its proper divisors (825409518959).
2112402313105 is an equidigital number, since it uses as much as digits as its factorization.
2112402313105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 850061376.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 2112402313105 its reverse (5013132042112), we get a palindrome (7125534355217).
The spelling of 2112402313105 in words is "two trillion, one hundred twelve billion, four hundred two million, three hundred thirteen thousand, one hundred five".
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