Base | Representation |
---|---|
bin | 1100010010111100010… |
… | …0110110101110010101 |
3 | 202012020220100101120022 |
4 | 3010233010312232111 |
5 | 11430111224340011 |
6 | 241013242514525 |
7 | 21155542365644 |
oct | 3045704665625 |
9 | 665226311508 |
10 | 211243199381 |
11 | 81651308315 |
12 | 34b34b05a45 |
13 | 16bc6747986 |
14 | a31d3bb35b |
15 | 57655528db |
hex | 312f136b95 |
211243199381 has 4 divisors (see below), whose sum is σ = 211279733472. Its totient is φ = 211206665292.
The previous prime is 211243199341. The next prime is 211243199407. The reversal of 211243199381 is 183991342112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211243199381 - 26 = 211243199317 is a prime.
It is a super-2 number, since 2×2112431993812 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211243199311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18258371 + ... + 18269936.
It is an arithmetic number, because the mean of its divisors is an integer number (52819933368).
Almost surely, 2211243199381 is an apocalyptic number.
It is an amenable number.
211243199381 is a deficient number, since it is larger than the sum of its proper divisors (36534091).
211243199381 is an equidigital number, since it uses as much as digits as its factorization.
211243199381 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36534090.
The product of its digits is 93312, while the sum is 44.
The spelling of 211243199381 in words is "two hundred eleven billion, two hundred forty-three million, one hundred ninety-nine thousand, three hundred eighty-one".
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