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21124331031 = 359271440393
BaseRepresentation
bin10011101011000110…
…111011011000010111
32000112012011012110210
4103223012323120113
5321230312043111
613412051420503
71345323564636
oct235306733027
960465135423
1021124331031
118a60152621
1241165b4733
131cb85c717b
14104575951d
1583980b0a6
hex4eb1bb617

21124331031 has 16 divisors (see below), whose sum is σ = 28748920320. Its totient is φ = 13793077440.

The previous prime is 21124331021. The next prime is 21124331047. The reversal of 21124331031 is 13013342112.

It is not a de Polignac number, because 21124331031 - 217 = 21124199959 is a prime.

It is a super-2 number, since 2×211243310312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21124330989 and 21124331007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21124331021) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 172230 + ... + 268163.

It is an arithmetic number, because the mean of its divisors is an integer number (1796807520).

Almost surely, 221124331031 is an apocalyptic number.

21124331031 is a deficient number, since it is larger than the sum of its proper divisors (7624589289).

21124331031 is a wasteful number, since it uses less digits than its factorization.

21124331031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 440726.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 21124331031 its reverse (13013342112), we get a palindrome (34137673143).

The spelling of 21124331031 in words is "twenty-one billion, one hundred twenty-four million, three hundred thirty-one thousand, thirty-one".

Divisors: 1 3 59 177 271 813 15989 47967 440393 1321179 25983187 77949561 119346503 358039509 7041443677 21124331031