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21124403103 = 37041467701
BaseRepresentation
bin10011101011000111…
…001100111110011111
32000112012021212100010
4103223013030332133
5321230321344403
613412053134303
71345324315026
oct235307147637
960465255303
1021124403103
118a601a1791
12411662a393
131cb8620c0b
1410457778bd
15839822603
hex4eb1ccf9f

21124403103 has 4 divisors (see below), whose sum is σ = 28165870808. Its totient is φ = 14082935400.

The previous prime is 21124403101. The next prime is 21124403143. The reversal of 21124403103 is 30130442112.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 21124403103 - 21 = 21124403101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21124403103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21124403101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3520733848 + ... + 3520733853.

It is an arithmetic number, because the mean of its divisors is an integer number (7041467702).

Almost surely, 221124403103 is an apocalyptic number.

21124403103 is a deficient number, since it is larger than the sum of its proper divisors (7041467705).

21124403103 is an equidigital number, since it uses as much as digits as its factorization.

21124403103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7041467704.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 21124403103 its reverse (30130442112), we get a palindrome (51254845215).

The spelling of 21124403103 in words is "twenty-one billion, one hundred twenty-four million, four hundred three thousand, one hundred three".

Divisors: 1 3 7041467701 21124403103