Base | Representation |
---|---|
bin | 11110101111011011011… |
… | …011001000001011000101 |
3 | 21110221202110202110012002 |
4 | 132233123123020023011 |
5 | 234102410111422010 |
6 | 4254250202235045 |
7 | 305423654653331 |
oct | 36573333101305 |
9 | 7427673673162 |
10 | 2112510264005 |
11 | 744a01a75449 |
12 | 2a15034b5a85 |
13 | 124293b4549b |
14 | 743631d67c1 |
15 | 39e4067c1a5 |
hex | 1ebdb6c82c5 |
2112510264005 has 4 divisors (see below), whose sum is σ = 2535012316812. Its totient is φ = 1690008211200.
The previous prime is 2112510263951. The next prime is 2112510264017. The reversal of 2112510264005 is 5004620152112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1448770915201 + 663739348804 = 1203649^2 + 814702^2 .
It is not a de Polignac number, because 2112510264005 - 214 = 2112510247621 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211251026396 + ... + 211251026405.
It is an arithmetic number, because the mean of its divisors is an integer number (633753079203).
Almost surely, 22112510264005 is an apocalyptic number.
It is an amenable number.
2112510264005 is a deficient number, since it is larger than the sum of its proper divisors (422502052807).
2112510264005 is an equidigital number, since it uses as much as digits as its factorization.
2112510264005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 422502052806.
The product of its (nonzero) digits is 4800, while the sum is 29.
The spelling of 2112510264005 in words is "two trillion, one hundred twelve billion, five hundred ten million, two hundred sixty-four thousand, five".
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